Laplacian Blob Detector Using Python
Scale-Space Blob Detection
Implementing a Laplacian blob detector in python from scratch
Features generated from Harris Corner Detector are not invariant to scale. For feature tracking, we need features which are invariant to affine transformations. Laplacian blob detector is one of the basic methods which generates features that are invariant to scaling.
The idea of a Laplacian blob detector is to convolve the image with a “blob filter” at multiple scales and look for extrema of filter response in the resulting scale space.
This filter generated by double derivating Gaussian filter along x and y-axis and adding them. Above is also known as Laplacian of Gaussian.
The output of the LOG filter is maximum when there is a corner in an image.
We want to find the characteristic scale of the blob, by convolving the image with different sigmas. But as we increase the sigma the response of blob filter with image decreases due to which we might not able to find a better scale. To reduce this effect we multiply the LOG filter σ square. This process is known as scale normalization.
The Laplacian archives maximum response for the binary circle of radius r is at σ=1.414*r
Above are some of the basics of the blob filter. The whole process boils down to two steps
- Convolve image with scale-normalized Laplacian at several scales (different scales means different sigma)
- Find maxima of squared Laplacian response in scale-space
Code for Laplacian Blob Detection
The code has four main steps:
- Generation of LOG filters
- Convolving the images with Gaussian filters
- Finding the maximum peak
- Drawing the blobs.
Generation of LOG filter
from pylab import *
import numpy as np
import matplotlib.pyplot as plt
img = cv2.imread("sunflowers.jpg",0) #gray scale conversion
from scipy import ndimage
from scipy.ndimage import filters
from scipy import spatial
k = 1.414
sigma = 1.0
img = img/255.0 #image normalization
n = np.ceil(sigma*6)
y,x = np.ogrid[-n//2:n//2+1,-n//2:n//2+1]
y_filter = np.exp(-(y*y/(2.*sigma*sigma)))
x_filter = np.exp(-(x*x/(2.*sigma*sigma)))
final_filter = (-(2*sigma**2) + (x*x + y*y) ) * (x_filter*y_filter) * (1/(2*np.pi*sigma**4))
LoG function takes sigma as input and generates a filter of size 6*sigma(best option).
Convolving the images with Gaussian filters
The images are convolved with different LOG filters
log_images =  #to store responses
for i in range(0,9):
y = np.power(k,i)
sigma_1 = sigma*y #sigma
filter_log = LoG(sigma_1) #filter generation
image = cv2.filter2D(img,-1,filter_log) # convolving image
image = np.pad(image,((1,1),(1,1)),'constant') #padding
image = np.square(image) # squaring the response
log_image_np = np.array([i for i in log_images]) # storing the #in numpy array
log_image_np = LoG_convolve(img)
To choose different sigma, I have multiplied sigma with k^i.The dimension of the log_image_np array will be z*image_height*image_width.where z represents the kth power that is multiplied to sigma.
In the above function, I have generated only 9 filters the plot of 9 filters are
Finding the maximum peak
co_ordinates =  #to store co ordinates
(h,w) = img.shape
for i in range(1,h):
for j in range(1,w):
slice_img = log_image_np[:,i-1:i+2,j-1:j+2] #9*3*3 slice
result = np.amax(slice_img) #finding maximum
if result >= 0.03: #threshold
z,x,y = np.unravel_index(slice_img.argmax(),slice_img.shape)
co_ordinates.append((i+x-1,j+y-1,k**z*sigma)) #finding co-rdinates
co_ordinates = list(set(detect_blob(log_image_np)))
At each pixel 3×3 neighborhood is considered in all scales which gives the 9x3x3 matrix. The maximum peak of the matrix is given by the maximum value of the matrix.
For every pixel, there will be a maximum. But not all pixels contribute to blobs. So we need to eliminate them by thresholding the peaks. This threshold is found by trial and error method.
If the maximum value is greater than the threshold then the point is considered and coordinate is stored.
(z,x,y) is the coordinates of the sliced image so we need to change them to original image coordinates. After changing them we will store them in the co_ordinates list and plot them.
fig, ax = plt.subplots()
nh,nw = img.shape
count = 0
for blob in co_ordinates:
y,x,r = blob
c = plt.Circle((x, y), r*1.414, color='red', linewidth=1.5, fill=False)
The above code draws the blob at each point in the stored list.
In the above image, we can find many blobs are overlapping. To reduce overlapped blobs we will find the area of overlap between blobs. If the area is greater than the threshold the blob with the smaller radius will be discarded.
#provided in scipy doucumentaion
def blob_overlap(blob1, blob2):
n_dim = len(blob1) - 1
root_ndim = sqrt(n_dim)
# radius of two blobs
r1 = blob1[-1] * root_ndim
r2 = blob2[-1] * root_ndim
d = sqrt(np.sum((blob1[:-1] - blob2[:-1])**2))
#no overlap between two blobs
if d > r1 + r2:
# one blob is inside the other, the smaller blob must die
elif d <= abs(r1 - r2):
#computing the area of overlap between blobs
ratio1 = (d ** 2 + r1 ** 2 - r2 ** 2) / (2 * d * r1)
ratio1 = np.clip(ratio1, -1, 1)
acos1 = math.acos(ratio1)
ratio2 = (d ** 2 + r2 ** 2 - r1 ** 2) / (2 * d * r2)
ratio2 = np.clip(ratio2, -1, 1)
acos2 = math.acos(ratio2)
a = -d + r2 + r1
b = d - r2 + r1
c = d + r2 - r1
d = d + r2 + r1
area = (r1 ** 2 * acos1 + r2 ** 2 * acos2 -0.5 * sqrt(abs(a * b * c * d)))
return area/(math.pi * (min(r1, r2) ** 2))
def redundancy(blobs_array, overlap):
sigma = blobs_array[:, -1].max()
distance = 2 * sigma * sqrt(blobs_array.shape - 1)
tree = spatial.cKDTree(blobs_array[:, :-1])
pairs = np.array(list(tree.query_pairs(distance)))
if len(pairs) == 0:
for (i, j) in pairs:
blob1, blob2 = blobs_array[i], blobs_array[j]
if blob_overlap(blob1, blob2) > overlap:
if blob1[-1] > blob2[-1]:
blob2[-1] = 0
blob1[-1] = 0
return np.array([b for b in blobs_array if b[-1] > 0])
co_ordinates = np.array(co_ordinates)
co_ordinates = redundancy(co_ordinates,0.5)
After removing overlapped blobs the output is
We can see that most of the blobs have been eliminated.
Link for the code in Github.
Thanks for reading. Any suggestions would be appreciated.
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